Optimal. Leaf size=214 \[ -\frac{2 b^3 (d+e x)^{7/2} (-4 a B e-A b e+5 b B d)}{7 e^6}+\frac{4 b^2 (d+e x)^{5/2} (b d-a e) (-3 a B e-2 A b e+5 b B d)}{5 e^6}-\frac{4 b (d+e x)^{3/2} (b d-a e)^2 (-2 a B e-3 A b e+5 b B d)}{3 e^6}+\frac{2 \sqrt{d+e x} (b d-a e)^3 (-a B e-4 A b e+5 b B d)}{e^6}+\frac{2 (b d-a e)^4 (B d-A e)}{e^6 \sqrt{d+e x}}+\frac{2 b^4 B (d+e x)^{9/2}}{9 e^6} \]
[Out]
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Rubi [A] time = 0.263882, antiderivative size = 214, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.061 \[ -\frac{2 b^3 (d+e x)^{7/2} (-4 a B e-A b e+5 b B d)}{7 e^6}+\frac{4 b^2 (d+e x)^{5/2} (b d-a e) (-3 a B e-2 A b e+5 b B d)}{5 e^6}-\frac{4 b (d+e x)^{3/2} (b d-a e)^2 (-2 a B e-3 A b e+5 b B d)}{3 e^6}+\frac{2 \sqrt{d+e x} (b d-a e)^3 (-a B e-4 A b e+5 b B d)}{e^6}+\frac{2 (b d-a e)^4 (B d-A e)}{e^6 \sqrt{d+e x}}+\frac{2 b^4 B (d+e x)^{9/2}}{9 e^6} \]
Antiderivative was successfully verified.
[In] Int[((A + B*x)*(a^2 + 2*a*b*x + b^2*x^2)^2)/(d + e*x)^(3/2),x]
[Out]
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Rubi in Sympy [A] time = 101.337, size = 218, normalized size = 1.02 \[ \frac{2 B b^{4} \left (d + e x\right )^{\frac{9}{2}}}{9 e^{6}} + \frac{2 b^{3} \left (d + e x\right )^{\frac{7}{2}} \left (A b e + 4 B a e - 5 B b d\right )}{7 e^{6}} + \frac{4 b^{2} \left (d + e x\right )^{\frac{5}{2}} \left (a e - b d\right ) \left (2 A b e + 3 B a e - 5 B b d\right )}{5 e^{6}} + \frac{4 b \left (d + e x\right )^{\frac{3}{2}} \left (a e - b d\right )^{2} \left (3 A b e + 2 B a e - 5 B b d\right )}{3 e^{6}} + \frac{2 \sqrt{d + e x} \left (a e - b d\right )^{3} \left (4 A b e + B a e - 5 B b d\right )}{e^{6}} - \frac{2 \left (A e - B d\right ) \left (a e - b d\right )^{4}}{e^{6} \sqrt{d + e x}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((B*x+A)*(b**2*x**2+2*a*b*x+a**2)**2/(e*x+d)**(3/2),x)
[Out]
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Mathematica [A] time = 0.429893, size = 335, normalized size = 1.57 \[ \frac{630 a^4 e^4 (-A e+2 B d+B e x)+840 a^3 b e^3 \left (3 A e (2 d+e x)+B \left (-8 d^2-4 d e x+e^2 x^2\right )\right )+252 a^2 b^2 e^2 \left (5 A e \left (-8 d^2-4 d e x+e^2 x^2\right )+3 B \left (16 d^3+8 d^2 e x-2 d e^2 x^2+e^3 x^3\right )\right )-72 a b^3 e \left (B \left (128 d^4+64 d^3 e x-16 d^2 e^2 x^2+8 d e^3 x^3-5 e^4 x^4\right )-7 A e \left (16 d^3+8 d^2 e x-2 d e^2 x^2+e^3 x^3\right )\right )+2 b^4 \left (9 A e \left (-128 d^4-64 d^3 e x+16 d^2 e^2 x^2-8 d e^3 x^3+5 e^4 x^4\right )+5 B \left (256 d^5+128 d^4 e x-32 d^3 e^2 x^2+16 d^2 e^3 x^3-10 d e^4 x^4+7 e^5 x^5\right )\right )}{315 e^6 \sqrt{d+e x}} \]
Antiderivative was successfully verified.
[In] Integrate[((A + B*x)*(a^2 + 2*a*b*x + b^2*x^2)^2)/(d + e*x)^(3/2),x]
[Out]
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Maple [B] time = 0.015, size = 469, normalized size = 2.2 \[ -{\frac{-70\,{b}^{4}B{x}^{5}{e}^{5}-90\,A{b}^{4}{e}^{5}{x}^{4}-360\,Ba{b}^{3}{e}^{5}{x}^{4}+100\,B{b}^{4}d{e}^{4}{x}^{4}-504\,Aa{b}^{3}{e}^{5}{x}^{3}+144\,A{b}^{4}d{e}^{4}{x}^{3}-756\,B{a}^{2}{b}^{2}{e}^{5}{x}^{3}+576\,Ba{b}^{3}d{e}^{4}{x}^{3}-160\,B{b}^{4}{d}^{2}{e}^{3}{x}^{3}-1260\,A{a}^{2}{b}^{2}{e}^{5}{x}^{2}+1008\,Aa{b}^{3}d{e}^{4}{x}^{2}-288\,A{b}^{4}{d}^{2}{e}^{3}{x}^{2}-840\,B{a}^{3}b{e}^{5}{x}^{2}+1512\,B{a}^{2}{b}^{2}d{e}^{4}{x}^{2}-1152\,Ba{b}^{3}{d}^{2}{e}^{3}{x}^{2}+320\,B{b}^{4}{d}^{3}{e}^{2}{x}^{2}-2520\,A{a}^{3}b{e}^{5}x+5040\,A{a}^{2}{b}^{2}d{e}^{4}x-4032\,Aa{b}^{3}{d}^{2}{e}^{3}x+1152\,A{b}^{4}{d}^{3}{e}^{2}x-630\,B{a}^{4}{e}^{5}x+3360\,B{a}^{3}bd{e}^{4}x-6048\,B{a}^{2}{b}^{2}{d}^{2}{e}^{3}x+4608\,Ba{b}^{3}{d}^{3}{e}^{2}x-1280\,B{b}^{4}{d}^{4}ex+630\,A{a}^{4}{e}^{5}-5040\,Ad{a}^{3}b{e}^{4}+10080\,A{a}^{2}{b}^{2}{d}^{2}{e}^{3}-8064\,Aa{b}^{3}{d}^{3}{e}^{2}+2304\,A{d}^{4}{b}^{4}e-1260\,B{a}^{4}d{e}^{4}+6720\,B{d}^{2}{a}^{3}b{e}^{3}-12096\,B{d}^{3}{a}^{2}{b}^{2}{e}^{2}+9216\,B{d}^{4}a{b}^{3}e-2560\,{b}^{4}B{d}^{5}}{315\,{e}^{6}}{\frac{1}{\sqrt{ex+d}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((B*x+A)*(b^2*x^2+2*a*b*x+a^2)^2/(e*x+d)^(3/2),x)
[Out]
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Maxima [A] time = 0.737314, size = 563, normalized size = 2.63 \[ \frac{2 \,{\left (\frac{35 \,{\left (e x + d\right )}^{\frac{9}{2}} B b^{4} - 45 \,{\left (5 \, B b^{4} d -{\left (4 \, B a b^{3} + A b^{4}\right )} e\right )}{\left (e x + d\right )}^{\frac{7}{2}} + 126 \,{\left (5 \, B b^{4} d^{2} - 2 \,{\left (4 \, B a b^{3} + A b^{4}\right )} d e +{\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} e^{2}\right )}{\left (e x + d\right )}^{\frac{5}{2}} - 210 \,{\left (5 \, B b^{4} d^{3} - 3 \,{\left (4 \, B a b^{3} + A b^{4}\right )} d^{2} e + 3 \,{\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} d e^{2} -{\left (2 \, B a^{3} b + 3 \, A a^{2} b^{2}\right )} e^{3}\right )}{\left (e x + d\right )}^{\frac{3}{2}} + 315 \,{\left (5 \, B b^{4} d^{4} - 4 \,{\left (4 \, B a b^{3} + A b^{4}\right )} d^{3} e + 6 \,{\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} d^{2} e^{2} - 4 \,{\left (2 \, B a^{3} b + 3 \, A a^{2} b^{2}\right )} d e^{3} +{\left (B a^{4} + 4 \, A a^{3} b\right )} e^{4}\right )} \sqrt{e x + d}}{e^{5}} + \frac{315 \,{\left (B b^{4} d^{5} - A a^{4} e^{5} -{\left (4 \, B a b^{3} + A b^{4}\right )} d^{4} e + 2 \,{\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} d^{3} e^{2} - 2 \,{\left (2 \, B a^{3} b + 3 \, A a^{2} b^{2}\right )} d^{2} e^{3} +{\left (B a^{4} + 4 \, A a^{3} b\right )} d e^{4}\right )}}{\sqrt{e x + d} e^{5}}\right )}}{315 \, e} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^2*(B*x + A)/(e*x + d)^(3/2),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.290443, size = 551, normalized size = 2.57 \[ \frac{2 \,{\left (35 \, B b^{4} e^{5} x^{5} + 1280 \, B b^{4} d^{5} - 315 \, A a^{4} e^{5} - 1152 \,{\left (4 \, B a b^{3} + A b^{4}\right )} d^{4} e + 2016 \,{\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} d^{3} e^{2} - 1680 \,{\left (2 \, B a^{3} b + 3 \, A a^{2} b^{2}\right )} d^{2} e^{3} + 630 \,{\left (B a^{4} + 4 \, A a^{3} b\right )} d e^{4} - 5 \,{\left (10 \, B b^{4} d e^{4} - 9 \,{\left (4 \, B a b^{3} + A b^{4}\right )} e^{5}\right )} x^{4} + 2 \,{\left (40 \, B b^{4} d^{2} e^{3} - 36 \,{\left (4 \, B a b^{3} + A b^{4}\right )} d e^{4} + 63 \,{\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} e^{5}\right )} x^{3} - 2 \,{\left (80 \, B b^{4} d^{3} e^{2} - 72 \,{\left (4 \, B a b^{3} + A b^{4}\right )} d^{2} e^{3} + 126 \,{\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} d e^{4} - 105 \,{\left (2 \, B a^{3} b + 3 \, A a^{2} b^{2}\right )} e^{5}\right )} x^{2} +{\left (640 \, B b^{4} d^{4} e - 576 \,{\left (4 \, B a b^{3} + A b^{4}\right )} d^{3} e^{2} + 1008 \,{\left (3 \, B a^{2} b^{2} + 2 \, A a b^{3}\right )} d^{2} e^{3} - 840 \,{\left (2 \, B a^{3} b + 3 \, A a^{2} b^{2}\right )} d e^{4} + 315 \,{\left (B a^{4} + 4 \, A a^{3} b\right )} e^{5}\right )} x\right )}}{315 \, \sqrt{e x + d} e^{6}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^2*(B*x + A)/(e*x + d)^(3/2),x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{\left (A + B x\right ) \left (a + b x\right )^{4}}{\left (d + e x\right )^{\frac{3}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x+A)*(b**2*x**2+2*a*b*x+a**2)**2/(e*x+d)**(3/2),x)
[Out]
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GIAC/XCAS [A] time = 0.288707, size = 792, normalized size = 3.7 \[ \frac{2}{315} \,{\left (35 \,{\left (x e + d\right )}^{\frac{9}{2}} B b^{4} e^{48} - 225 \,{\left (x e + d\right )}^{\frac{7}{2}} B b^{4} d e^{48} + 630 \,{\left (x e + d\right )}^{\frac{5}{2}} B b^{4} d^{2} e^{48} - 1050 \,{\left (x e + d\right )}^{\frac{3}{2}} B b^{4} d^{3} e^{48} + 1575 \, \sqrt{x e + d} B b^{4} d^{4} e^{48} + 180 \,{\left (x e + d\right )}^{\frac{7}{2}} B a b^{3} e^{49} + 45 \,{\left (x e + d\right )}^{\frac{7}{2}} A b^{4} e^{49} - 1008 \,{\left (x e + d\right )}^{\frac{5}{2}} B a b^{3} d e^{49} - 252 \,{\left (x e + d\right )}^{\frac{5}{2}} A b^{4} d e^{49} + 2520 \,{\left (x e + d\right )}^{\frac{3}{2}} B a b^{3} d^{2} e^{49} + 630 \,{\left (x e + d\right )}^{\frac{3}{2}} A b^{4} d^{2} e^{49} - 5040 \, \sqrt{x e + d} B a b^{3} d^{3} e^{49} - 1260 \, \sqrt{x e + d} A b^{4} d^{3} e^{49} + 378 \,{\left (x e + d\right )}^{\frac{5}{2}} B a^{2} b^{2} e^{50} + 252 \,{\left (x e + d\right )}^{\frac{5}{2}} A a b^{3} e^{50} - 1890 \,{\left (x e + d\right )}^{\frac{3}{2}} B a^{2} b^{2} d e^{50} - 1260 \,{\left (x e + d\right )}^{\frac{3}{2}} A a b^{3} d e^{50} + 5670 \, \sqrt{x e + d} B a^{2} b^{2} d^{2} e^{50} + 3780 \, \sqrt{x e + d} A a b^{3} d^{2} e^{50} + 420 \,{\left (x e + d\right )}^{\frac{3}{2}} B a^{3} b e^{51} + 630 \,{\left (x e + d\right )}^{\frac{3}{2}} A a^{2} b^{2} e^{51} - 2520 \, \sqrt{x e + d} B a^{3} b d e^{51} - 3780 \, \sqrt{x e + d} A a^{2} b^{2} d e^{51} + 315 \, \sqrt{x e + d} B a^{4} e^{52} + 1260 \, \sqrt{x e + d} A a^{3} b e^{52}\right )} e^{\left (-54\right )} + \frac{2 \,{\left (B b^{4} d^{5} - 4 \, B a b^{3} d^{4} e - A b^{4} d^{4} e + 6 \, B a^{2} b^{2} d^{3} e^{2} + 4 \, A a b^{3} d^{3} e^{2} - 4 \, B a^{3} b d^{2} e^{3} - 6 \, A a^{2} b^{2} d^{2} e^{3} + B a^{4} d e^{4} + 4 \, A a^{3} b d e^{4} - A a^{4} e^{5}\right )} e^{\left (-6\right )}}{\sqrt{x e + d}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^2*(B*x + A)/(e*x + d)^(3/2),x, algorithm="giac")
[Out]